11-13-2012, 08:45 PM
I visited my friend over the weekend and we played Last Night On Earth a couple times again. In the round where he played as zombies, a card came up and we had a question for clarification.
I forget the exact name of the card without looking and am not near my game, so if anybody can fill us in out that, I'd appreciate it. I also don't remember the exact wording. However, the basic jist was...
Roll a D6. Place that many zombies from your zombie pool each into a different space already occupied by another zombie.
The card specifies DIFFERENT space. In other words, you can't roll a 6 and decide to put all 6 zombies in the same space as another zombie already on the board.
The question came in because my friend actually rolled more than the number of spaces currently containing any zombies. He had a bunch of zombies on the board, but some spaces had multiple zombies. So, just for example, say he rolled a 6 but only currently had zombies on 4 different spaces...
In that example, does the zombie player then get to double up and place a couple zombies in the same place...
OR
Since it specifically said "DIFFERENT space" does this mean, that in that case, the zombie player would technically lose those last two zombies, only getting to place four on the board? Any thoughts, folks?
I forget the exact name of the card without looking and am not near my game, so if anybody can fill us in out that, I'd appreciate it. I also don't remember the exact wording. However, the basic jist was...
Roll a D6. Place that many zombies from your zombie pool each into a different space already occupied by another zombie.
The card specifies DIFFERENT space. In other words, you can't roll a 6 and decide to put all 6 zombies in the same space as another zombie already on the board.
The question came in because my friend actually rolled more than the number of spaces currently containing any zombies. He had a bunch of zombies on the board, but some spaces had multiple zombies. So, just for example, say he rolled a 6 but only currently had zombies on 4 different spaces...
In that example, does the zombie player then get to double up and place a couple zombies in the same place...
OR
Since it specifically said "DIFFERENT space" does this mean, that in that case, the zombie player would technically lose those last two zombies, only getting to place four on the board? Any thoughts, folks?